標題:

Trigonometry

發問:

How to express cos 36 degree in surd form ? Please explain, thanks.

最佳解答:

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As cos 36°=sin 54°, let θ=18°, so,cos 2θ=sin 3θ==> 1-2sin2θ=3sin θ-4sin3θ==> 4sin3θ-2sin2θ-3sin θ+1=0==> (sin θ-1)(4sin2θ+2sin θ-1)=0==> sin θ=1 or (-1+√5)/4 or (-1-√5)/4As sin 18° has a positive value less than 1, so sin 18°=(-1+√5)/4,Therefore,cos 36°=1-2sin218°=1-2[(-1+√5)/4]2=1-(3-√5)/4=(1+√5)/4

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