標題:
數學....................緊急!!!!!!!!!!!!!!1
發問:
但係English: Peter has $9 more than Paul, and Philip’s is 1/3(1 over 3 三分一) of Peter’s.How much money does each of them have if they a total of $61? Use the equation(方程式).
最佳解答:
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let Peter has $x,Paul has $(x-9) and Philip has $x/3 then x+x-9+x/3=61 7x=210 x=30 so Peter has $30 Paul has 30-9=$21 Philip has 30/3=$10
其他解答:
Let Peter's money is x: x + (x-9) + x/3 = 61 2x + x/3 = 70 (6x+x)/3 =70 7x=70*3 x=30 Therefore, Peter has $30, Paul has $21, Philip has $10.|||||Let x be the amount of money Peter has x-9+x+1/3x=61 2又1/3x=70 x=30 So,Peter has $30 , Paul has $21 and Philip has $10 . 2006-10-13 20:40:40 補充： Let $x be
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