標題:
How to factorise (x^4 - 1) to (x^2+1)(x+1)(x-1)?
發問:
How to factorise (x^4 - 1) to (x^2+1)(x+1)(x-1)?
最佳解答:
Use a^2-b^2=(a+b)(a-b) two times (x^4 - 1) =(x^2+1)(x^2-1) [first time] =(x^2+1)(x+1)(x-1) [second time]
其他解答:
How to factorise (x^4 - 1) to (x^2+1)(x+1)(x-1)?
發問:
How to factorise (x^4 - 1) to (x^2+1)(x+1)(x-1)?
最佳解答:
Use a^2-b^2=(a+b)(a-b) two times (x^4 - 1) =(x^2+1)(x^2-1) [first time] =(x^2+1)(x+1)(x-1) [second time]
其他解答:
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首先,利用A^2-B^2=(A+B)(A-B)既公式: (x^2+1) (x^2-1) 注意:只可以-數先用得以上既公式, 所以(x^2+1)保留~ (x^2+1) (x+1)(x-1) OK.
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